Question

to
V5
Illustration 18.
Find the moment of inertia of the ring shown in figure about the axis AB.
Solution.
From parallel axes theorem,
MR2
3.
TAB = ICM + MR2 = + MR2
MR2
2
2
Illustration 19.
R-B​

Answer 1

Answer:

to

toV5

toV5Illustration 18.

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR2

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.TAB = ICM + MR2 = + MR2

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.TAB = ICM + MR2 = + MR2MR2

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.TAB = ICM + MR2 = + MR2MR22

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.TAB = ICM + MR2 = + MR2MR222

toV5Illustration 18.Find the moment of inertia of the ring shown in figure about the axis AB.Solution.From parallel axes theorem,MR23.TAB = ICM + MR2 = + MR2MR222Illustration 19.

R-B