To verify that the relation r in the set a of all line in a plan, defined by R, R={(l, m) } is symmetry but neither reflexive nor transitive
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Step-by-step explanation:
Given the relation R is defined as R={(L
1
,L
2
):L
1
⊥L
2
}.
Now this relation is not reflexive as
L
1
R
L
1
does not hold as every line is not perpendicular to itself.
The relation is symmetric as
L
1
R
L
2
gives
L
2
R
L
1
. [ As if L
1
is perpendicular to L
2
then L
2
is also perpendicular to L
1
].
The relation is not transitive as
L
1
R
L
2
,
L
2
R
L
3
does not gives
L
1
R
L
3
. [ As, if L
1
is perpendicular to L
2
and L
2
is perpendicular to L
3
then L
1
may of may not be perpendicular to L
3
]
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