Question

To what potential must a insulated sphere of radius 10 cm be charged so that the surface density of charge is equal to 1μC/m².​

Answer 1

Here V=?,r=14cm=14×10−2m

σ=1μCm−2=10−6Cm−2

V=q4π∈0r=14π∈0(σ.4πr2r)

=14π∈0(4πrσ)

=9×109×4×227×14×10−2×10−6

V=15840v