To what pressure would you have to compress 48.0 L of oxygen gas at 99.3 kPa in order to reduce its volume to 16.0 L?
Answers
Answered by
1
Answer:
298
k
P
a
Explanation:
The answer can be determined by using Boyle's Law:
Let's identify our known and unknown variables.
Knowns:
P
1
= 99.3 kpa
V
1
= 48.0 L
V
2
= 16.0 L
Unknowns:
P
2
Rearrange the equation to solve for the final pressure by dividing both sides by
V
2
to get
P
2
by itself like this:
P
2
=
P
1
×
V
1
V
2
Plug in your given values to obtain the final pressure:
P
2
=
99.3
k
P
a
×
48.0
L
16.0
L
=
298
k
P
a
Similar questions