Question

To what temperature must a gas at 300 K be cooled down in order to reduce its volume to 1/3rdof its original volume, pressure remaining constant?

Answer 1

Gas equation-
P¹*V¹/T¹= P²*V²/T²
V¹/T¹= V²/T² (as P is constant)
V¹/300= V¹/3*T²
T²=100K
so, gas should be cool down to 100K.

Answer 2

The answers is..P¹*V¹/T¹= P²*V²/T² V¹/T¹= V²/T² (as P is constant) V¹/300= V¹/3*T² T²=100K..so it must cool down to this