Question

to what temperature must a given mass of oxygen at zero degree celsius be heated so that both its volume and pressure will be doubled

Answer 1

Answer:

ideal gas law:

pV =nRT

We're assuming temperature is the deciding factor to change pressure and volume

2p * 2V = nR * (x)T

Since the right side changes by a factor of 4 (2 from the pressure times 2 from the volume), temperature must increase by a factor of 4. However, the question states an initial condition of 0C (which, using standard units, is about 273 Kelvin). Therefore, temperature much go up to 1092 Kelvin, or 819C.