Question

to what temperature must a neon gas sample be heated to double it's pressure if the initial volume of gas at 75 degree Celsius is decreased by 15.0percent

Answer 1

Check this attachment :-)

Answer 2

Answer:

318.6°

Explanation:

According to ideal gas equation PV = RT

We know T = 75 ° = (75+273)k= 348k

For initial condition PV=R×348 ....(i)

For final condition

2P×0.85V= R× T ....(ii)

By solving equation (i) and equation (ii), we get

T= 591.6 K = 318.6°

The gas is heated upto 318.6° temperature