Question

To win a game, Keshav wanted a total of 7. What is the probability of winning a game by Keshav? if 2 dice​

Answer 1

Step-by-step explanation:

A win 7:1,6

6,1

p(A)=

36

6

=

6

1

3,4

4,3

2,5

5,2

B win 10

4,6 P(B)=

36

3

6,4

5,5 =

12

1

B wins ⇒ P(Alosc) P(B win)

+P(Alosc)P(Blose)P(Alosc)P(Bwin)

+...

=

6

5

×

12

1

+

6

5

×

12

11

×

6

5

×

12

1

+...

=

1−

72

55

72

5

=

17

5

Answer 2

Answer :

Probability of getting sum as 7  $=\frac{1}{6}$

Given:

when two dice are thrown, Keshav wanted a total of 7.

To find:

Probability of getting sum as 7

Explanation:

From the question, we have

Favorable outcomes = (1, 6) (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

Total number of outcomes = 6 × 6 = 36

Probability of getting sum as 7  =

$=\frac{Favorable outcome}{Total outcome} \\=\frac{6}{36} \\=\frac{1}{6}$

Probability:

The term probability refers to possibility. Probability deals with the occurrence of a random event. There is a 0 to 1 value range. To determine the possibility of certain events, probability has been applied in mathematics. The chances of anything happening is often referred to as probability. You can better understand the outcomes of a random experiment by applying this fundamental theorem of probability, which also remains true for the probability distribution. Use probability to evaluate a situation as actually chances of happening.

To learn more about probability visit:

brainly.in/question/54143022

brainly.in/question/40651896

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