Question

to
(x+y)+2(x+y)+1 is equivalent
(a) (x+y+1)(x+y=1)
(c) (x-y-1)(x-y-1)
(b) (x-y+1)(x+y-1)
(d) (x+1+1) (x+y+1)​

Answer 1

Step-by-step explanation:

a is the right answer

hope it help you

Answer 2

/* There is mistake in the question . It must be like this */

$Given \: (x+y)^{2}+2(x+y)+1 \\= (x+y)^{2} + 2\times (x+y) \times 1 + 1^{2} \\= [(x+y)+ 1]^{2}$

/* By Algebraic Identity */

$\boxed{\pink{ a^{2}+2ab+b^{2} = (a+b)^{2} }}$

$= (x+y+1)^{2} \\= (x+y+1)(x+y+1)$

Therefore.,

$\red{ (x+y)^{2}+2(x+y)+1 \: is \: equivalent \: to } \\\green {= (x+y+1)(x+y+1)}$

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