Question

today is my birthday please help me only math Aryabhatta please answer this question​

Answer 1

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Q.1) a + ( b + c ) = ( a + b ) + c

➭ Substitute the values,

-» -25+ [20+ (-10) = [(-25) +20] + (-10)

Solve the RHS with brackets first,

Solve the LHS with brackets first,

-» -25 + 10 = [(-25) +20] + (-10)

Add the integers in LHS,

-» -15= [(-25) +20] + (-10)

-» -15=(-5)+ (-10) Add the integers in RHS,

-» -15= -15

Comparing both sides,

LHS = RHS

Thus, verified.

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2) a × (b + c) = a × b + a × c

Solution: Substitute the values,

-» -25 x [20+ (-10)] = (-25) × 20 + (-25) × (-10)

Solve the LHS with brackets first,

-» -25 x 10 = (-25) 20+ (-25) (-10)

Multiply the integers,

-» 250 = (-25) x 20 + (-25) × (-10)

Solve the RHS using BODMAS rule,

-» -250 = -500 + 250

Add the integers,

-» -250 = -250

Comparing both sides,

LHS = RHS

Thus, verified.

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