today Mr Nelson is four times old as his son find 4 year hence Mr Nelson would be 3 times as old as son then find the present age of Mr Nelson
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let Mr. Nelson's age be x years
and his son's age be y years
Ist case
x=4y
x-4y=0 ___________________1
2nd case
Mr.Nelson's age = (x+4)
his son's age =(y+4)
ATQ
x+4 = 3(y+4)
x+4=3y+12
x-3y=8_________________2
solving 1 and 2
x - 4y = 0
x - 3y = 8
(-) (+). (-)
_________
-y= -8
y=8
putting y in 1
x-4y=0
x-4*8=0
x=32
so Mr.Nelson's present age = x years = 32 years
His son's present age =y years = 8 years
and his son's age be y years
Ist case
x=4y
x-4y=0 ___________________1
2nd case
Mr.Nelson's age = (x+4)
his son's age =(y+4)
ATQ
x+4 = 3(y+4)
x+4=3y+12
x-3y=8_________________2
solving 1 and 2
x - 4y = 0
x - 3y = 8
(-) (+). (-)
_________
-y= -8
y=8
putting y in 1
x-4y=0
x-4*8=0
x=32
so Mr.Nelson's present age = x years = 32 years
His son's present age =y years = 8 years
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