Question

Today's physics Interesting Question.
Don't scam for 5 points.​

Answer 1

Answer:

Given,

Force F = 21 N

Mass of A block $m_A$ = 1 kg

Mass of B block $m_B$ = 2 kg

To find:

The force which is applied on A block = $F_1$

Now,

Two block will move forward at the same acceleration. Thus, they will have common acceleration (a) .

So common acceleration is :

$\sf \: a = \frac{F}{ m_A + m_B} = \frac{21}{1 + 2} = 7\: \: m {s}^{ - 2}$

$\sf \: force \: \: \: F_1 = m_A \times a \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 \times 7 \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 7 \: N \:$