Question

Together A & B can do a job in 16 days. A alone can do a job in 24 days. If they

worked together for 6 days & then B went away. How long did A take to

complete the unfinished part of the job?​

Answer 1

Answer:

A very easy and simple trick.

A+B=16 days

A=24 days

So, let's take LCM of 16 and 24. That's 48.

Notr: This 48 unit is the total work to be done.

So, A and B do (48/16) = 3 unit work/day …(1)

And, A does (48/24) = 2 unit work/day …(2)

Equation(1)-(2)

{A+B-A=3–2=1}

B does (3–2)= 1 unit/day

So, Total days required = (Total work)/(unit per day)

That is B can do it in (48/1)=48 days.

Thanks

Answer 2

$\purple{ \mathfrak{ \underline{Solution}}}$

A + B complete work n 16 days

A + B complete 1/16 of work in 1 day

A completes work in 24 days

A completes 1/24 of work in 1 day

Subtract A’s work from A + B’s work to get B’s work in 1 day:

1/16 - 1/24

= 3/48 - 2/48

= 1/48 in 1 day

Therefore, it will take B 48 days to complete

Hence,the answer is 48 days.

❣Hope this helps you mate✌