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Answer:
1/x-3 +1/x+3=1/x²-9
x+3+x-3/(x-3)(x+3)=1/x²-9
2x/x²-9=1/x²-9
cancelling the denominator from both sides
2x=1
x=1/2
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1/x_3 +1/x+3 =1/x^2 _9
Take left hand side
1/x_3 +1/x+3
Take LCM
(x+3)+(x_3)/(x_3)(x+3)
(x+3)+(x_3) These will cancel eachother
So....
1/(x_3)(x+3)
1/x^2+3x_3x_3^2
+3x _3x cancel eachother
1/x^2_3^2
1/x^2_9
So....
Left hand side = right hand side
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