Question

Tolgonametri
The diagonal AC, BD of a rhombus AB CD meet at
o If AD = 8 cm and BD = 6cm. Find cost angle OAD​

Answer 1

Answer:

diagonals AC and BD of a rhombus ABCD meet at O

Diagonals of a Rhombus perpendicularlly bisect each other

=> AO = OC = AC/2 = 8/2 = 4 cm

Similalrly

BO = OD = BD/2 = 6/2 = 3 Cm

in Δ OCD

OC = 4 cm

OD = 3 cm

CD² = OC² + OD²

=> CD² = 4² + 3²

=> CD² = 25

=> CD = 5 cm

sin ∠OCD = OD/CD

=> Sin∠OCD = 3/5

hope it help you