Question

Tom and Alice are the parents of four children. Tom has earlobes that are not attached to the side of his head, which is a dominant trait. Alice has earlobes that are attached, which is a recessive trait. Use the two Punnett squares ("E" represents the dominant earlobe gene, and "e" represents the recessive earlobe gene) to answer the following questions.

What must be true about the earlobes of Alice's parents?

Which Punnett square allows for the possibility that Tom and Alice's children have attached earlobes?

What is the likelihood that the children in square 1 will have earlobes that are not attached?

What is the likelihood that the children in square 2 will have earlobes that are not attached?

Think About It
What does probability have to do with heredity

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Answer 1

Answer:

Explanation:

Alice's Parents are of a few possibilities...

1. Alice can have a heterozygous mother and father.

E       e

E e $\left[\begin{array}{cc}EE&Ee\\Ee&ee\end{array}\right]$

Probability of ear lobe being attached : 1/4

Probability of ear lobe not being attached : 3/4

1. Alice can have Homozygous dominant parent and a Heterozygous recessive PARENT.

E       e

 ee $\left[\begin{array}{cc}Ee&ee\\Ee&ee\end{array}\right]$

Probability of ear lobe being attached : 2/4= 1/2

Probability of ear lobe being attached : 2/4=1/2

If Tom is heterozygous then , and alice is homozygous recessive(ee)

     E       e

 ee $\left[\begin{array}{cc}Ee&ee\\Ee&ee\end{array}\right]$

Here two children dont have attached ear lobes (the left side Both).

Possibility : 2/4

=1/2

Probability of ear lobe being attached : 1/2

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