Question

Tom and bob have a total of 49 toys. If Bob has 5 more toys than Tom. How many toys does each one have?

Answer 1

tom = (49 - 5) / 2

44/2

22 toys

Bob = 49-22

27 toys

Answer 2

Solution:-

Let the no. of toys Tom have, be 'x'

Therefore, no. of toys Bob have=(x+5)

Total no. of toys = 49

According to question,

=> x + (x + 5) = 49

=> x + x + 5 = 49

=> 2x + 5 = 49

=> 2x = 49 - 5

=> 2x = 49 - 5=> 2x = 44

=> x = 44/2

=> x = 44/2

=> x = 22

Therefore, No. of toys Tom have is 22 and no. of toys Bob have is (22+5)= 27.

Basic information:-

•Whole numbers - Whole numbers are numbers without fractions. For example:- 0,1,2,3,4,5,6..... and so on.

•Natural numbers:- Natural numbers are also numbers without fractions but they don't consist of zero. For example:- 1,2,3,4,5,6,7.....and so on

•Integers:- An integer is number which is not a fraction and can be positive, negative or 0. For example:- ......-3,-2,-1,0,1,2,3..... and so on.

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