Math, asked by Sonal1871, 1 year ago

Tom and Bob have a total of 49 toys. If Bob has 5 more toys than Tom, how many toys does each one have? ( A ) Tom: 22 , Bob: 27 ( B ) None of these ( C ) Tom: 20 , Bob: 27 ( D ) Tom: 27 , Bob: 22

Answers

Answered by minakshiyewale

Answer:

(A)

Step-by-step explanation:

Adding them we get 49 and

Bob has 5 more then

Tom :22. Bob : 27.

Answered by Anonymous

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Answer:

( A ) Tom: 22 , Bob: 27

Step-by-step explanation:

It is stated that,

Tom and Bob together have 49 toys.

Bob has 5 more toys than that of Tom.

Let, Tom has 'x' toys

∴ Bob has = (x+5) toys

According to the problem,

$x+(x+5) = 49\\⇒ (x+x+5) = 49\\⇒ 2x +5 = 49\\⇒ 2x = 49-5\\⇒ 2x = 44\\⇒ x = 44/2\\⇒ x = 22$

∴ Tom has 22 toys.

∴ Bob has (22+5)

= 27 toys.

∴ Option (A) is correct that is, Tom has 22 toys and Bob has 27 toys.

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