Question

Tom is moving
in a well designed park
of a special shape. He is moving
with 2 m/s and turnss by 60° in
every 2 seconds. Then after 6 second
net displacement of Tom is.



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Answer 1

Answer:

0 m

Explanation:

in 6 sec he turns 6×60=360 degrees

he returns to his starting position so net displacement is 0

Answer 2

The net displacement of Tom is 2 meters.

GIVEN

Tom is moving in a well designed park

of a special shape. He is moving with 2 m/s and turns by 60° in every 2 seconds.

TO FIND

Then after 6 seconds net displacement of Tom.

SOLUTION

We can simply solve the above problem as follows;

Let Tom starts at a point O and ends his journey at C.

It is given that,

Speed of Tom = 2m/s

Time taken = 2 seconds

Distance travelled in 1 second = 2/2 = 1 meter

Now,

Displacement = OC

So,

OC = OAcos60° + BCcos60° + AB

= 1/2 + 1/2 + 1

= 2meters

Hence, The net displacement of Tom is 2 meters.

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