Tongkat konduktor yang panjangnya 1 m beeputar dengan kecepatan sudut tetap sebesar 10 rad/s didalam daerah bermedan magnet homogen 0,1 T. Sumbu putaran tersebut melalui salah satu ujung tongkat sejajar dengan arah garis - garis gaya medan magnet diatas. GGL induksi antara kedua ujung tongkat
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Explanation:
Given Tongkat konduktor yang panjangnya 1 m beeputar dengan kecepatan sudut tetap sebesar 10 rad/s didalam daerah bermedan magnet homogen 0,1 T. Sumbu putaran tersebut melalui salah satu ujung tongkat sejajar dengan arah garis - garis gaya medan magnet diatas. GGL induksi antara kedua ujung tongkat
Given a conductor stick whose length is 1 m rotates with a fixed angular velocity of 10 rad / s in an area with a uniform magnetic field B = 0.1 T. the axis of rotation is through one end of the stick and is parallel to the direction of the magnetic field lines above. The emf that is induced between the two ends of the stick (in V) i
- Now the stick let say A and B is rotating and the velocity is 10 rad / s
- So ω = 10 rad/s
- Also given Bh = 0.1 T
- So the stick rotates with an angular velocity of 10 rad/s.
- So we need to find the induced emf
- Induced emf e is given by
- So e = B ω l^2 / 2
- = 0.1 x 10 x 1 / 2
- = 0.1 x 5
- = 0.5 volts
Reference link will be
https://brainly.co.id/tugas/8893796
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