Question

took
At a social sports club with 290 members in it. It was found that 120 played tennis
110 played tennikoit, 130 played Badminton, 70 played both tennis and tennikoit, 55
played tennikoit and Badminton, 60 played tennis and Badminton. It was also
discovered that 75 members had joined only for the social side of the club and did not
play any of the three games. How many played all the three games.​

Answer 1

Answer:

no.of members play all the three games is 15

Step-by-step explanation:

total members= 290

mebers play tennis n(t)=120

members play tennikoit n(tk)=110

members play badminton n(b)=130

members play tennis and tennikoit n(t ^ tk)= 70

members play tennikoit and badminton n(tk^b)=55

members play badminton and tennis n(t ^ b)=60

members play nothing is 75

members play all the three games n(t^tk^b)

n(tUtkUb)= n(t)+n(tk)+n(b)-n(t^tk)-n(tk^b)-n(t^b)+n(t^tk^b)

therefore n(t^tk^b)= n(tUtkUb)-(n(t)+n(tk)+n(b)-n(t^tk)-n(tk^b)-n(t^b))

n(t^tk^b)= 290-(120+110+130-70-55-60)

n(t^tk^b)= 290-275= 15

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