top of ladder of length 15m reaches the distance between the base of the wall and that of ladder?
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Let's be -:
The window is A
The base of the wall B
The base of the ladder C
and The distance between the base of the wall and the base of the ladder be X
By using the formula -:
[ Hypotenuse]² = [ base ]²+ [ height]²
[ AC]² = [ BC ]² + [AB]²
[ 15 ]² = [ X ]² + [ 9 ]²
225 = X² + 81
X = 225 - 81
[ X ]² = 144 m
X = 12 m
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