Question

Top surface of a raised platform is in the shape of a regular octagon as shown in adjoining figure. Find the area of the octagonal surface pls sahi answer dena faltu mai koi bhi answer mat likh dena and jo sahi answer dega with pura process ke sath usko branliest answer kar dunga ​

Answer 1

Answer:

rectangular park is 45 m long and 30 m wide. A path of 3.5 m wide is constructed outside the park.

The area of the inner rectangle is 1350 sq. cm.

And Area of the outer rectangle is 1924 sq. m

Step-by-step explanation:

A rectangular park is 45 m long and 30 m wide.

Area of park = l \times b = 45 \times 30 = 1350 sq. m=l×b=45×30=1350sq.m

So area of inner rectangle is 1350 sq. cm

Now length of outer rectangle = (45 + 3.5 + 3.5 )= 52 m=(45+3.5+3.5)=52m

And breadth = (30 + 3.5 + 3.5) = 37=(30+3.5+3.5)=37

So Area of the outer rectangle= l \times b = 52 \times 37 = 1924 sq. m=l×b=52×37=1924sq.m