Question

Topic: Age Problems
1. A boy is 5 times as old as his sister. Two years ago the sum of the squares of
their ages was 170. Find the present age of sister.​

Answer 1

Answer:

B=5*S

Now (B-2)^2

+(S-2)^2

=170

Step-by-step explanation:

So (5s-2-2)^2

+(s-2)^2

=170

so (25s^2+16-40s)

+(s^2+4-4s)

=170

so 26s^2+20-44s

=13s^2+10-22s=170

so13 s square - 22s-160=0

Then i don't know.

Answer 2

(x-2)^2+(5x-2)^2=170
(x^2)+4-4x+(25x^2)+4-10x=170
27x^2-14x-162=0
After that IDK