Question

Topic: Circles

Calculate:
(i) ∠CDB
(ii) ∠ABC
(iii) ∠ACB

Note:
• Diagram is attached.
• Spams/Plagiarism strictly prohibited.​

Answer 1

$\large \sf \underline{SOLUTION :}$

$\bf(1).. \sf \: \: \angle CDB = \angle BAC = 49 ^\circ$

$\bf(2).. \sf \: \: \angle ABC = \angle ADC = 43 ^\circ$

• Angle subtend by same chord are equal in circle.

$\bf(3).. \sf \: \: In \: \triangle \: ABC,$

$\sf \longrightarrow \: \angle ABC + \angle BCA + \angle CAB= 180 ^\circ \: \:$

• By Angle Sum Property

$\sf \longrightarrow \: 43 ^\circ + \angle ACB+ 49 ^\circ= 180 ^\circ \: \:$

$\sf \longrightarrow \: \angle ACB= 180 ^\circ - 49 \degree-43 ^\circ \: \:$

$\sf \longrightarrow \: \angle ACB= 88 ^\circ \: \:$