Topic:- CROSS MULTIPLICATION METHOD
Q3. From a bus stand in Delhi, if we buy 2 tickets to Pitampura and 3 tickets to Dilshad Garden, the total cost is Rs 46 but if we buy 3 tickets to Pitampura and 5 tickets to Dilshad Garden, the total cost is Rs 74. Find the fares from the bus stand to Pitampura and to Dilshad Garden. Form a pair of linear equations from above data and solve it by cross- multiplication method. Also, verify the solution.
Standard:- 10
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Answered by
33
Heya!
Here is yr answer.....
T = ticket (s)
Suppose, the price of T frm delhi to pitampura is x
The price of the T to dilshad garden is y
The price of the 2T from delhi to pitampura and 3T to dilshad garden = 46
2x + 3y = 46
2x + 3y - 46 = 0 ------(1)
The price of 3 T to pitampura and 5 T to dilshad garden = 74
3x + 5y = 74
3x + 5y - 74 = 0 ------(2)
Cross multiplication of (1) & (2)
2x + 3y - 46 = 0
3x + 5y - 74 = 0
Price of T to pitampura = 8
Price of T to dilshad garden = 10
________________________
2(8)+3(10) = 46
16 + 30 = 46
46 = 46
LHS = RHS
__________________________
3(8) + 5(10) = 74
24 + 50 = 74
74 =74
LHS = RHS
__________________________
Hope it hlpz...
Here is yr answer.....
T = ticket (s)
Suppose, the price of T frm delhi to pitampura is x
The price of the T to dilshad garden is y
The price of the 2T from delhi to pitampura and 3T to dilshad garden = 46
2x + 3y = 46
2x + 3y - 46 = 0 ------(1)
The price of 3 T to pitampura and 5 T to dilshad garden = 74
3x + 5y = 74
3x + 5y - 74 = 0 ------(2)
Cross multiplication of (1) & (2)
2x + 3y - 46 = 0
3x + 5y - 74 = 0
Price of T to pitampura = 8
Price of T to dilshad garden = 10
________________________
2(8)+3(10) = 46
16 + 30 = 46
46 = 46
LHS = RHS
__________________________
3(8) + 5(10) = 74
24 + 50 = 74
74 =74
LHS = RHS
__________________________
Hope it hlpz...
VijayaLaxmiMehra1:
its wrong
Answered by
11
let
2X+3Y=46---1 st equation
3X+5Y=74---2 nd equation
(1st equation)-(2nd equation)
1st equation × 5 = 10X+15Y=230
2nd equation×3 = 9X+15Y=222
--------------------------------------------
X= 8
1. The cost of one ticket from bus stand to Pitampura is Rs=8
then substitute X=8 in 1st equation
2×8+3Y=46
16+3Y=46
3Y=46-16
3Y=30
Y=30/3
Y=10
2.The cost of one ticket from bus stand to Dilshad Garden is Rs=10
Now check your answer
2×8+10×3=46
3×8+10×5=74
now the answer is also cross checked
2X+3Y=46---1 st equation
3X+5Y=74---2 nd equation
(1st equation)-(2nd equation)
1st equation × 5 = 10X+15Y=230
2nd equation×3 = 9X+15Y=222
--------------------------------------------
X= 8
1. The cost of one ticket from bus stand to Pitampura is Rs=8
then substitute X=8 in 1st equation
2×8+3Y=46
16+3Y=46
3Y=46-16
3Y=30
Y=30/3
Y=10
2.The cost of one ticket from bus stand to Dilshad Garden is Rs=10
Now check your answer
2×8+10×3=46
3×8+10×5=74
now the answer is also cross checked
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