Question

Topic :- Electrostatics [Class 12]

Objects A,B and C are three insulated, spherical conductors of radii R, 2R and 3R respectively. Originally, A and B have charges of +3 mc whereas C has a charge of -6 mc. Objects A and C are touched and moved apart. Calculate the new charges appears over A, B and C.​

Answer 1

Question:

Objects A,B and C are three insulated, spherical conductors of radii R, 2R and 3R respectively. Originally, A and B have charges of +3 mc whereas C has a charge of -6 mc. Objects A and C are touched and moved apart. Calculate the new charges appears over A, B and C.

Solution:

Charge on A = +3mC

Charge on B = +3mC

Charge on C = - 6mC

After touching A and C, charges will be equally distributed among both.

After touching, let the charge on them be q.

$q= \frac{+3 + (-6)}{2} \\\\ q= \frac{-3}{2} \\\\ q= - 1.5 mC.$

New charge over A is - 1.5 mC, charge over B remains unchanged (+3mC) and charge over C is same as A i.e = - 1.5 mC.

Answer 2

Explanation:

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