Question

Topic: Linear equation in two variables
Class: 10

Qᴜᴇsᴛɪᴏɴ: The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically.


︎︎︎ ᴇxᴘᴇᴄᴛɪɴɢ ᴀɴsᴡᴇʀ ғʀᴏᴍ:
➪Bʀᴀɪɴʟʏ ᴍᴏᴅᴇʀᴀᴛᴏʀs
➪Bʀᴀɪɴʟʏ sᴛᴀʀs
➪Bʀᴀɪɴʟʏ ᴛᴇᴀᴄʜᴇʀs
➪Oᴛʜᴇʀ ʙᴇsᴛ ᴜsᴇʀs

Important notes: ☞︎︎︎I ᴡᴀɴᴛ ᴘʀᴏᴘᴇʀ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ
☞︎︎︎Nᴏ ᴄᴏᴘʏ ᴘᴀsᴛᴇ ᴀɴsᴡᴇʀ
☞︎︎︎ Nᴏ sᴘᴀᴍ

꧁Aʟʟ ᴛʜᴇ ʙᴇsᴛ꧂​

Answer 1

Answer:

x  65  55  45  35

y  20  40  60  80

Let the cost of 1 kg of apples be x and that of 1 kg be y

So the algebraic representation can be as follows:

2x+y=160

4x+2y=300⇒2x+y=150

The situation can be represented graphically by plotting these two equations.

2x+y=160⇒y=160−2x

x  70  60  50  40

y=160−2x  20  40  60  80

2x+y=150⇒y=150−2x

x  65  55  45  35

y=150−2x  20  40  60  80

We can see that the lines do not intersect anywhere, i.e. they are parallel. Hence we can not arrive at a solution.

Step-by-step explanation:

Answer 2

Question:

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically.

Answer:

2x + y = 150

&

4x + 2y = ₹300

Step-by-step explanation:

Let the cost of 1kg apple be rs.x and the cost of 1kg grapes be rs.y .

So, for the first purchase,

= 2 × Rs x + 1 × Rs y = ₹ 160

= 2x + y = 160

So, After a month the cost of 4kg apples and 2kg grapes is ₹300

So, 4x + 2y = 300