Question

Topic :Trigonometry


solve it!

︵‿︵( °-°)︵‿︵​

Answer 1

We know that range of

$\sqrt{ {a}^{2} + {b}^{2} } \geqslant a \sin(x) + b \cos(x) \geqslant - \sqrt{ {a}^{2} + {b}^{2} }$

here

$a = 7$

and

$b = 24$

so Max value of

$a \sin(x ) + b \cos(x) = 25$

and minimum value of

$a \sin(x) + b \cos(x) = - 25$

NOTE: I assumed variable x in place of theta becoz theta was not there.