Math, asked by Parvani3871, 5 hours ago

Topics: Cellular Communication fundamentals
Question:
Consider that you have been hired by a cellular company looking to extend its cellular services in one of the developing sectors in ISLAMABAD covering an area of 400Km2 such that length of one side of a cell is 1500m. The one-sided system bandwidth is 25MHz with 150KHz Channel spacing.
i. Find area of the cell?
ii. How many times the cluster size has to be replicated to cover the entire cellular area?
iii. Calculate the total no. of voice channels in one sector if there are 42 control channels per cluster and each RF channel is to be time shared among 6 users.
iv. Find the mean () , considering pathloss exponent = 3.5
v. The traffic is uniform with average call holding time of 100 sec and call blocking during system busy hour is 2 %. Calculate the calls per hour per cell site and spectral efficiency
Use N = 4, 60o sectorization (for Odd roll numbers)
N = 7, 120o sectorization (for Even roll numbers)

Answers

Answered by navneetsingh61206
0

Answer:

Topics: Cellular Communication fundamentals

Question:

Consider that you have been hired by a cellular company looking to extend its cellular services in one of the developing sectors in ISLAMABAD covering an area of 400Km2 such that length of one side of a cell is 1500m. The one-sided system bandwidth is 25MHz with 150KHz Channel spacing.

i. Find area of the cell?

ii. How many times the cluster size has to be replicated to cover the entire cellular area?

iii. Calculate the total no. of voice channels in one sector if there are 42 control channels per cluster and each RF channel is to be time shared among 6 users.

iv. Find the mean () , considering pathloss exponent = 3.5

v. The traffic is uniform with average call holding time of 100 sec and call blocking during system busy hour is 2 %. Calculate the calls per hour per cell site and spectral efficiency

Use N = 4, 60o sectorization (for Odd roll numbers)

N = 7, 120o sectorization (for Even roll numbers)

Step-by-step explanation:

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