Question

topics Special type of Equation Determinant.
1) Solve 5x +10y = 35; 10x + 5y =40.​

Answer 1

Step-by-step explanation:

5x + 10y = 35 ..........(1)

10x + 5y = 40 ..........(2)

Now,

x = 35 - 10y / 5 ........(3)

By putting the value of x in equal (2)

10( 35 - 10y /5 ) + 5y = 40

2( 35 - 10y) + 5y = 40

70 - 20y + 5y = 40

70 - 15y = 40

- 15y = 40 - 70

- 15y = - 30

y = 2

By putting the value of y in eq (1)

5x + 10(2) = 35

5x + 20 = 35

5x = 35 - 20

5x = 15

x = 3

I hope this may help you....

Answer 2

Answer:

x=3,y=2 is the correct answer

Step-by-step explanation:

5x+10y=35--(1)

10x+5y=40--(2)

multiply eq.(2)*2,then

20x+10y=80--(3)

subtact eq.(1) and (3)

20x+10y=80--(3)

5x+10y=35--(1)

_-__-___-_____

15x+0=45

15x=45

x=45/15

x=3

put the value of x in eq.(1)

5x+10y=35--(1)

5*3+10y=35

15+10y=35

10y=35-15

10y=20

y=20/10

y=2