Question

Toricelli’s barometer used mercury. Pascal duplicated it using French wine of density 984 kg m–3. Determine the height of the wine column for normal atmospheric pressure.​

Answer 1

Explanation:

Density of mercury, ρ1 = 13.6 × 103 kg/m3

Height of the mercury column, h1 = 0.76 m

Density of French wine, ρ2 = 984 kg/m3

Height of the French wine column = h2

Acceleration due to gravity, g = 9.8 m/s2

The pressure in both the columns is equal, i.e.,

Pressure in the mercury column = Pressure in the French wine column

ρ1h1g = ρ2h2g

h2 = ρ1h1 / ρ2

= 13.6 × 103 × 0.76 / 984 = 10.5 m

Hence, the height of the French wine column for normal atmospheric pressure is 10.5 m.

Answer 2

Answer:

We know,

P = dhg

Where d is dnesity. g is accⁿ due to gravity and h is the height of liquid column.

Here, atmospheric pressure (P) = 1.013 × 10^5 Pa

density of French wire(d) = 984 Kg/m³

g = 9.8 m/s²

h = ?

h = P/dg

= 1.013 × 10^5/984×9.8

= 10.5 m