Physics, asked by jack6778, 10 months ago

Toricelli’s barometer used mercury. Pascal duplicated it using French wine of density 984 kg m–3. Determine the height of the wine column for normal atmospheric pressure.

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Answered by Anonymous
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Refer the attachment.

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Answered by Anonymous
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Answer:

Density of mercury, $$\rho_1= 13.6 \times 10^3 kg/m3$$

Height of the mercury column, $$h_1=0.76m$$

Density of French wine, $$\rho_2=984\, kg/m3$$

Height of the French wine column $$=h_2$$

Acceleration due to gravity, $$g=9.8m/s^2$$

The pressure in both the columns is equal, i.e.,

Pressure in the mercury column $$=$$ Pressure in the French wine column

$$\rho_1h_1g = \rho_2h_2g$$

$$h_2 = \rho_1h_1 / \rho_2$$

$$= 13.6 \times 10^3 \times 0.76 / 984 = 10.5\ m$$

Hence, the height of the French wine column for normal atmospheric pressure is 10.5 m.

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