Question

Torque of 1500Nm is acting on a body produces an angular acceleration of 3.2rad/s^2. Find M.I. of the body.

Answer 1

Answer:

468.75Kgm2

use formula

Torque = I × alpha

Answer 2

$I=468.75\ kg.m^2$ is the momentum of inertia.

Explanation:

Given:

Torque on the body, $T=1500\ N.m$

angular acceleration of the body, $\alpha=3.2\ rad.s^{-2}$

The moment of inertia is given as:

$I=\frac{\tau}{\alpha}$

$I=\frac{1500}{3.2}$

$I=468.75\ kg.m^2$

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TOPIC: moment of inertia

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