Physics, asked by TYPRANAVSRIRAM, 5 months ago

Torque of force 6i about point (0,0,3) is

Answers

Answered by sarimkhan18

1

Answer:

Torque =r×F

=(oi^+0j^+3k^)×(6i^)

=18k^

Answered by saravind590432

0

Answer:

-18k

Explanation:

Torque= r×f

=(0i +0j+ 3k) × 6i

= -18k

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