Question

Torsional rigidity of a solid circular shaft of diameter d is proportional to

Answer 1

Answer:

T ∝ d⁴

torisonal rigidity of a solid circular shaft is proportional to fourth power of its diameter d

Explanation:

If G is the modulus of rigidity and J is the Polar moment of inertia then the torisonal rigidity is given by GJ

For a solid circular shaft of diameter d, the polar moment of inertia

$\boxed{J=\frac{\pi d^4}{32}}$

Therefore,

$\boxed{\text{Torisonal Rigidity}=GJ=\frac{\pi d^4G}{32}}}$

Thus the torisonal rigidity is proportional to fourth tower of its diameter d