Question

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Example an
HE 21
LMH13003
Now, HCF ICM23,00 63,003
Product of numbers - 32763,003
Product of numbers Product or their cF and Me
in the corne number is to and their product and the Martwa number
IM - Hot Product of numbers
Thus
LCM - Product of numbers
400
1
Hence, ICM of two numbers is 400.
We knows
Solution
2,400
HICH
Exercise 2(C)
Objective Type Que
1. Fill in the blanks.
Using the result HCF LCM Product of numbers
First Number
Second Number
1 CM
28
Ose
20
140
110
16
15
60
28
d)
88​

Answer 1

Answer:

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Step-by-step explanation:

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