History, asked by itzmesona, 2 months ago

Toss 3 coins together. Record the appearance of head and tails on each coin( find the probability)
. 1. 2 heads
2.No head
3. 1 head
4. 2 tails​

Answers

Answered by llItzDishantll
4

Answer:

Total number of possible outcomes = 2

(i) If the favourable outcome is head (H).

Number of favourable outcomes = 1.

Therefore, P(getting a head)

Number of favorable outcomes

= P(H) = total number of possible outcomes

= 1/2.

(ii) If the favourable outcome is tail (T).

Number of favourable outcomes = 1.

Therefore, P(getting a tail)

Number of favorable outcomes

= P(T) = total number of possible outcomes

= 1/2.

Answered by lIMrKaminalI
11

Explanation:

  • getting two heads:

Let E1 = event of getting 2 heads. Then,

E1 = {HH} and, therefore, n(E1) = 1.

Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.

  • getting no head:

Let E4 = event of getting no head. Then,

E4 = {TT} and, therefore, n(E4) = 1.

Therefore, P(getting no head) = P(E4) = n(E4)/n(S) = ¼.

  • getting at least 1 head:

Let E6 = event of getting at least 1 head. Then,

E6 = {HT, TH, HH} and, therefore, n(E6) = 3.

Therefore, P(getting at least 1 head) = P(E6) = n(E6)/n(S) = ¾.

  • getting two tails:

Let E2 = event of getting 2 tails. Then,

E2 = {TT} and, therefore, n(E2) = 1.

Therefore, P(getting 2 tails) = P(E2) = n(E2)/n(S) = 1/4.

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