Question

Total 469 coins consists of 1 rs ,50ps,25ps,coins whose total amount 280.find the no of 50 ps coins

Answer 1

Step-by-step explanation:

number of coins = total value of those coins/ value of one coin

total value of 1 rs , 0.5 rs and 0.25 rs coins are 5x , 3x and x respectively

number of 1 rupee coin = a = 5x/1 = 5x

number of 0.5 rupee coin = b = 3x/0.5 = 6x

number of 0.25 rupee coin = c = x/0.25 = 4x

N = total number of coins = 465

N = a + b + c

465 = 5x + 6x + 4x

x (15) = 465

x = 465/15

x = 31

number of 1 rupee coin = a = 5x = 5x 31 = 155

number of 0.5 rupee coin = b = 6x = 6 x 31 = 186

number of 0.25 rupee coin = c  = 4x = 4 (31) = 124

Answer 2

Answer:

The number of 50 paisa coins in the total 469 coins were 378.

Step-by-step explanation:

To calculate the total number of 50 paisa coins in a bunch of 469 coins, we must follow the following steps:

1. Assumptions:  Let the number of Rupee 1 coins, be $x$,  and 50 paisa coins be $y$, also 25 paisa coins be $z$
2. From the given question, we can derive the equation as, $x+ y+z= 469$. This is be the equation1.
3. Another information is the total amount from those coins are Rs 280. And as we know 2 coins of 50 paisa amounts to 1 rupee. similarly, 4 coins of 25 paisa amounts to 1 rupee, we can derive that: $x + y/2 +z/4 = 280$, This is be the equation 2.
4. Upon rearranging equation1 and equation2, we get: $(4x+2y+z)/4=280$
5. On solving both the equations for $x, y, and, z$, we get: $x=91, y=378, z=0$

Therefore, the number of 50 paisa coins are 378.