Math, asked by kumarhitesh53121, 1 year ago

total age of 3 person is 93.. 10 years ago the ratio of their ages was 2:3:4what is the present age of them

Answers

Answered by adityadubey17
0

Step-by-step explanation:

we can subtract 30 to 93 to increase the age to meet it to present age

93-30=63

for finding the ages

2x+3x+4x=63

9x=63

x=63/9

x=7

2x=2*7=14

3x=3*7=21

4x=4*7=28

after 10year

1 person =14+10=24

2person =21+10=31

3person =28+10=38

Answered by hirak143
0

Answer:

24,31,38

Step-by-step explanation:

total \: age  \: of  \: 3  \: person  \: is  \: 93 \:  \\ 10 \:  years \:  ago  \: their  \: total  \: ages  \: was \:  (93-30) = 63 \\ 10 \:  years  \: ago  \: ratio  \: of  \: their \:  ages  \: was  \: 2:3:4 \\ the \: ages \: are \: 2x,3x,4x \\ \\ Conditionally\\  (2x + 3x + 4x) = 6 \\ 9x = 63 \\ x = 7 \\  \\ 10 \:  years \:  ago  \: their \: age  \: was \:  \: (2x) = 14,(3x) = 21,(4x) = 28 \\  \\ present \: age \: is , \:  \\ (14 + 10) = 24 \\ (21 + 10) = 31 \\ (28 + 10) = 38

Similar questions