Total charge present on one mole of Phosphide ion in coulombs?
Answers
Well, the charge on a single electron is 1.6 x 10^-16 Coulomb, and there are 6.02 x 10^23 electrons per mole, so the charge will be (1.6 x 10^-16) x (6.02 x 10^23) = 96500 C which is called 1 Faraday.
if we recall that an Ampere corresponds to a charge flow of 1 Coulomb each second and further, use the fact that the charge on a monovalent ion is approximately 1.6 x 10-19 Coulombs (that is 1 electron or 1 proton charge), then we see that a current of about one pA corresponds to roughly 107 ions passing through
Answer:
Molar mass of PO43- = 95 g / mole
Explanation:
PO43- means atom has gained 3 electrons. We will first calculate the mass of these 3-electrons.
Gained mass = 3 x 9.1091x10-28 (mass of electron) x 6.022x1023 (Avogadro's constant) = 0.00164565 g / mole.
Molar mass of PO43- = 95 g / mole
19 g of PO43- means = 19 / 95 moles = 0.2 moles.
Ions in 0.2 moles = 0.2 x 6.022 x 1023 = 1.2044 x 1023 ions.
Charge on each ion = 3 x 1.602 x 10-19 = 4.806 x 10-19 coulombs.
So, charge of 19g of PO43-ions = 1.2044 x 1023 x 4.806 x 10-19 coulombs = 5.78 x 104 Coulombs.