total cost of a table and a chair is ₹ 600.if the cost of the table is twice the cost of the chair , find the cost of each item
Answers
Answer:
Simple! The cost of each item is as follows:
1) Cost of Chair is ₹ 200
2) Cost of Table is ₹ 400
Explanation:
Now move to the solution!
As according to the given requirements, we have
Cost of a Chair + Cost of a Table = total cost ( Cost of a table and a chair = ₹ 600 )
Now as cost of a table is twice as the cost of a chair, so
Cost of a Chair + 2 × (Cost of a Chair ) = total cost ( Cost of a table and a chair = ₹ 600 )
Now put "X" in the place of "Cost of a Chair" , So we have ;
X + 2(X) = total cost ( Cost of a table and a chair = ₹ 600 )
Simply put the total cost at the place of "total cost ( Cost of a table and a chair = ₹ 600 )" as given in the question,
X + 2×(X) = ₹ 600 (Equation #1)
As we know that X + 2×(X) = 3X , so putting 3X in left side of the equation! We have ;
3X = ₹ 600
Now find the value of X , by dividing 3 on the right hand side!
X = ₹ 600 ÷ 3
X = ₹ 200
Now putting value of X in the above equation named as "equation #1" , So we will get the following Equation!
₹ 200 + 2(₹ 200) = ₹ 600
And this equation "₹ 200 + 2(₹ 200) = ₹ 600 " make sense !
So Cost of each item is as follows;
1) Cost of Chair = X = ₹ 200
2) Cost of Table = 2(X) = ₹ 400
Regards
Mr.Khattak ツ