Question

total electrons present in 0.5 mole of O2+

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Answer 1

Answer:

1 gram atom refers to the the atomic weight of an element.

Therefore, 1 g-atom of oxygen = 16g

1 g-atom = 0.5 mole

Hence, 1 g-atom contains 0.5 × Avagadro number of atoms

As oxygen exists in diatomic state, 1 molecule of oxygen contains 2 atoms of oxygen.  

Therfore, the answer is 1/4 times Avagadro number of molecules

Hope it helps :)

Answer 2

Answer:

here is your answer

1 gram atom refers to the the atomic weight of an element.

Therefore, 1 g-atom of oxygen = 16g

1 g-atom = 0.5 mole

Hence, 1 g-atom contains 0.5 × Avagadro number of atoms

As oxygen exists in diatomic state, 1 molecule of oxygen contains 2 atoms of oxygen.

Therfore, the answer is 1/4 times Avagadro number of molecules