Question

Total Energy, kinetic Energy and potential Energy in eV/atom present in first excited Bohr's orbit of H-atom are respectively​

Answer 1

Answer:

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Explanation:

These relations have nothing to do with the choice of the zero of potential energy. Now, choosing the zero of potential energy at infinity, we have V=−(Ze

2

/4πε

0

r), which gives V=−2T and E=T+v=−T.

(a) The quoted value of E = 3.4 eV is based on the customary choice of zero of potential energy at infinity. Using E = T, the kinetic energy of the electron in this state is + 3.4 eV.

(b) Using V = 2T, potential energy of the electron is = 6.8 eV.

(c) If the zero of potential energy is chosen differently, kinetic energy does not change. Its value is + 3.4 eV independent of the choice of the zero of potential energy. The potential energy, and the total energy of the state, however, would alter if a different zero of the potential energy is chosen