Question

Total energy obtained from 38 ATP is_kj
(1)1298
(2)1398
(3)1292
(4)1392

Answer 1

Answer:

option 3 1292 is the answer

if it right plz comment me

Answer 2

ANSWER : 3) 1292

Explanation:

1 ATP = 7.3 Kcal

So, 38 ATP = 7.3 × 38 = 277.4 Kcal

But , in ques value of energy is asked in KJ :

=> 1 cal = 4.2 J

=>. 1 Kcal = 4.2 × 10^3 J = 4.2 KJ

=> 277.4 Kcal = 4.2 × 277.4 KJ = 1292 KJ