Question

Total impulse imposed by ball of mass 2 kg to the ball of mass 4 kg has the magnitude equal to

Answer 1

The magnitude of impulse on the ball is 5 Ns.

Explanation:

Correct statement:

a ball of mass 0.5 kg moving with a speed of 6 m/s collides perpendicularly with a vertical wall and bounces off with a speed of 4 m/s in opposite direction .The magnitude of impulse on the ball is ?

Given data:

Mass of ball = 0.5 Kg

Initial velocity "vi" = 6 m/s

Final velocity "vf" 4 m/s

Solution:

The magnitude of the impulse will be the change of momentum

p = mv1−(−mv2)

  =m(v1+v2)

   =0.5×10 =   5 Ns

Thus the magnitude of impulse on the ball is 5 Ns.

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