Question

Total K.E. of a sample of a gas which contain 1×10²² molecules is 500 cal at -73⁰C. Another sample of a gas at 127⁰C has a total kinetic energy of 1500 cals. Then the number of molecules in the second sample of gas is

A) 3×10²²
B) 2.5×10²²
C) 1.5×10²²
D) 4×10²²​

Answer 1

Answer:

I think A is correct

Explanation:

will help

Answer 2

Answer:

a is the correct answer