Total kinetic energy of two moles
an Ideal Gas at 127°C is
(1) 8.31 kJ (2) 9.98 kJ
(3) 3.20 kj (4) 5.68 kJ
Answers
Answered by
2
Answer:
9.98kj
Explanation:
KE=3/2nRT
KE = 3×2×8.314×400/2
= 9.98kj
Answered by
2
Explanation:
9.98kg is the answer..
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