Total mechanical energy of freely falling body is constand
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Answered by
0
Answer:
Yes it is constant.
Explanation:
Mechanical energy =K.E + P.E
Answered by
0
Answer:
Explanation:
Let the energy of particle at any height = E
Initial energy = 1\2 mv 2 +mgH
=0+mgH=Eo
Velocity at any height = v
∴v 2 =u 2 +2as
v 2 =0+2(−g)[−(H−h)]
=2g(H−h)
∴E= 1\2 mv 2 +mgh
= m\2 .2g(H−h)+mgh=mgH=E o
Hence constant
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