Total monthly income of A,B & C is ₹32,200. They spend 75%, 80% and 60% respectively. If their savings are in ratio of 4:3:6 then calculate difference between income of A and that of B+C?
Answers
Step-by-step explanation:
Let the ratio of salary of A, B, C be x, y, z respectively. Sum of salary x+y+z = 72000 Rs
Spending 80% , 85% , 75%
Savings 20x:15y:25z => 4x:3y:5z = 8:9:20
=> x =2 , y=3, z=4
Therefore salary ratio A:B:C = x:y:z = 2:3:4
Salary of A = 72000 x 2/(2+3+4)
= 72000x2/9= 16000 Rs = answer
Verification:
Salary of A = Rs 16000 (already calculated)
Salary of B = Rs 24000 <= (72000×3/9)
Salary of C = Rs 320000 <=(72000×4/9)
Total salary = 16000+24000+32000=72000 => true.
Savings of A:B:C => (100-80)×16000/100 : (100-85)×24000/100: (100-75)×32000/100= 3200:3600:8000
=> 8:9:20 ---- true.
Therefore the Answer, A's salary = Rs16000 is correct .
Answer:
9800
Step-by-step explanation:
LET A,B,C be the salary
A+B+C=32,200
EXPENDITURE:
exp A=75% of A =(75/100)A=3A/4
exp B=1B/5
exp C=2C/5
SAVINGS:
SALARY-EXPENDITURE
FOR A. A-3A/4 = 1A/4
FOR B. 1B/5
FOR C. 2C/5
SAVINGS RATIO
4:3:6
4x
3x
6x
therefore,
4x=1A/4.
A = 16X
SIMILARLY
3x = 1B/5
15x=B
15x = C
As A+B+C=32,200
16x+15x+15x=32,200
46x=32,200
x=700
A = 16X = 11200
B+C= 30x = 21000
difference is 21000 -11200 = 98000